2x^2-8x-9x+36=0

Solution for 2x^2-8x-9x+36=0 equation:

2x^2-8x-9x+36=0

We add all the numbers together, and all the variables

2x^2-17x+36=0

a = 2; b = -17; c = +36;
Δ = b2-4ac
Δ = -172-4·2·36
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-1}{2*2}=\frac{16}{4}
=4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+1}{2*2}=\frac{18}{4}
=4+1/2
$